Python 按照字典值对字典进行排序
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方法一:
>>> xs = {'a': 4, 'b': 3, 'c': 2, 'd': 1} >>> sorted(xs.items(), key=lambda item: item[1]) [('d', 1), ('c', 2), ('b', 3), ('a', 4)]
- 方法二:
>>> xs = {'a': 4, 'b': 3, 'c': 2, 'd': 1} >>> import operator >>> sorted(xs.items(), key=operator.itemgetter(1)) [('d', 1), ('c', 2), ('b', 3), ('a', 4)]
`单行代码`
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