Go函数接收可变参数

简单案例

package main

import(
    "fmt"
    "reflect"
)

func receiveSlice(manyints ...int) { //该函数可接收多个int参数, 打包为[]int类型slice
    fmt.Println(reflect.TypeOf(manyints), len(manyints), cap(manyints))
    fmt.Printf("%#v \n",manyints)
}
func receiveFourInts(var1, var2, var3, var4 int){
    fmt.Printf("%#v%#v%#v%#v",var1, var2, var3, var4)
}

func main(){
    receiveSlice(1,2,3,4)
    receiveSlice(1,2,3,4,5,6,7,8)
    slice := []int{1,2,3,4}
    //receiveSlice(slice) //报错
    //receiveFourInts(slice...) //报错, var...用法只能用于接收参数为 ...type的函数
    receiveSlice(slice...) //正常
}

执行结果

[]int 4 4
[]int{1, 2, 3, 4} 
[]int 8 8
[]int{1, 2, 3, 4, 5, 6, 7, 8} 
[]int 4 4
[]int{1, 2, 3, 4}

使用场景

xorm 动态拼接数据的时候

    //更新表2 eb_crm_good_check_log
    sql2, err2 := dbs.UpdateHelperObject.UpdateBatchByIds(updateGoodCheckData, mysql.EbCrmGoodCheckLogObject.TableName())
    if nil != err2 {
        Logger.LoggersHelperObject.PanicAndLog("PushHDGoodControllerRun.148", err2)
    }
    _, err22 := session.Exec(sql2...)