Laravel 框架中 使用 Symfony 提供的方法 抛出不同类型错误异常

Symfony\Component\HttpKernel\Exception\BadRequestHttpException 400
Symfony\Component\HttpKernel\Exception\UnauthorizedHttpException 401
Symfony\Component\HttpKernel\Exception\AccessDeniedHttpException 403
Symfony\Component\HttpKernel\Exception\NotFoundHttpException 404
Symfony\Component\HttpKernel\Exception\MethodNotAllowedHttpException 405
Symfony\Component\HttpKernel\Exception\NotAcceptableHttpException 406
Symfony\Component\HttpKernel\Exception\ConflictHttpException 409
Symfony\Component\HttpKernel\Exception\GoneHttpException 410
Symfony\Component\HttpKernel\Exception\LengthRequiredHttpException 411
Symfony\Component\HttpKernel\Exception\PreconditionFailedHttpException 412
Symfony\Component\HttpKernel\Exception\UnsupportedMediaTypeHttpException 415
Symfony\Component\HttpKernel\Exception\PreconditionRequiredHttpException 428
Symfony\Component\HttpKernel\Exception\TooManyRequestsHttpException 429
Symfony\Component\HttpKernel\Exception\HttpException 500
Symfony\Component\HttpKernel\Exception\ServiceUnavailableHttpException 503

在需要抛出对应类型的错误的时候,只需要引入上面对应的 异常处理类,调用对应 方法就可以
例如 抛出一个404错误
throw new BadRequestHttpException('请求的资源不存在!');

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