EasyTree 一个生成树型数据结构最简单的方式
前言
最近在做公司的项目开发,类似CMS的一个系统,尤其是这个分类,是让我特别头疼的,各种不方便。其实就是一个树型结构的数组(PS:刚开始做,分类的数据都是写死的),在开发完任务以后,忙里偷闲自己写了一个library,欢迎各位大佬指出不合适的地方,小弟虚心改进 :smile:
安装
$ composer require lambert/tree-shape
今早刚发布,还热乎的,:joy:
使用
use Lambert\TreeShape\Manager;
$category = [
['id' => 1, 'name' => '节点1', 'pid' => 0],
['id' => 2, 'name' => '节点2', 'pid' => 0],
['id' => 3, 'name' => '节点3', 'pid' => 1],
['id' => 4, 'name' => '节点4', 'pid' => 1],
];
// Start build
$manager = Manager::buildTree($category, 'pid');
$tree = $manager->all();
生成后结构为:
Array
(
[1] => Lambert\TreeShape\Tree Object
(
[childrenIds:protected] => Array
(
[0] => 3
[1] => 4
)
[recursionChildrenIds:protected] =>
[currentNode:protected] => Lambert\TreeShape\Node Object
(
[data:protected] => Array
(
[id] => 1
[name] => 节点1
[pid] => 0
)
)
[leftTree:protected] =>
[rightTree:protected] => Array
(
[3] => Lambert\TreeShape\Tree Object
(
[childrenIds:protected] =>
[recursionChildrenIds:protected] =>
[currentNode:protected] => Lambert\TreeShape\Node Object
(
[data:protected] => Array
(
[id] => 3
[name] => 节点3
[pid] => 1
)
)
[leftTree:protected] => Lambert\TreeShape\Tree Object
*RECURSION*
[rightTree:protected] =>
)
[4] => Lambert\TreeShape\Tree Object
(
[childrenIds:protected] =>
[recursionChildrenIds:protected] =>
[currentNode:protected] => Lambert\TreeShape\Node Object
(
[data:protected] => Array
(
[id] => 4
[name] => 节点4
[pid] => 1
)
)
[leftTree:protected] => Lambert\TreeShape\Tree Object
*RECURSION*
[rightTree:protected] =>
)
)
)
[2] => Lambert\TreeShape\Tree Object
(
[childrenIds:protected] =>
[recursionChildrenIds:protected] =>
[currentNode:protected] => Lambert\TreeShape\Node Object
(
[data:protected] => Array
(
[id] => 2
[name] => 节点2
[pid] => 0
)
)
[leftTree:protected] =>
[rightTree:protected] =>
)
)
Methods
-
查找某个Tree
$tree = $manager->findTree('name', '子节点1');
-
获取当前树的左子树
$leftTree = $tree->getLeftTree();
-
获取当前树的右子树
$rightTree = $tree->getRightTree();
注意:这里如果是多个右子树,则为Array
-
获取当前树的节点
$node = $tree->getCurrentNode();
-
获取节点属性
继承了ArrayAccess,可以使用数组或属性的方式访问 $node['name'] or $node->name; // 节点1 $node['id'] or $node->id; // 1 ...
如果客官觉得还行,别吝啬,给小弟一个大大赞吧,附上地址github
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本帖由系统于 6年前 自动加精
666
@overtrue 多谢超哥点赞,晚上回去吃鸡啊
@Such丶
@overtrue :smirk:
@overtrue 同求吃鸡
@YuxiangDong 没收到你的邀请哦
@overtrue steam id多少?
@qqww11 overtrue
@overtrue 不是overfalse吗?
@里暮色中 overfalse 是吃鸡账号。。。不是 steam 账号
@overtrue 我以为是一样的。。。
$manager->all()->toArray() 能转数组吗
@mingyun 还木有:joy:
很赞:+1: