PHP接收post时，数据合闭的问题

array_combine()

为啥不一步到位，直接接收二维数组呢？

$post1 = ['张三', '李四', '王五'];
$post2 = ['20岁', '25岁', '40岁'];
$peopleList = [];
foreach ($post1 as $k => $name) {
    $people = new stdClass();
    $people->name = $name;
    $people->title = $post2[$k] ?? '';
    $peopleList[] = $people;
}
print_r($peopleList);

$post1 = ['张三', '李四', '王五'];
$post2 = ['20 岁', '25 岁', '40 岁'];

$result = array_map(function($name, $title) {
    $obj = new stdClass();
    $obj->name = $name;
    $obj->title = $title;
    return $obj;
}, $post1, $post2);

// 打印结果
print_r($result);

人工智能的回答：

<?php  
$post1 = ['张三', '李四', '王五'];  
$post2 = ['20 岁', '25 岁', '40 岁'];  

// 确保两个数组长度相同  
if (count($post1) !== count($post2)) {  
    throw new Exception("两个数组的长度不相同，无法合并。");  
}  

// 使用array_map创建新的对象数组  
$result = array_map(function($name, $title) {  
    $obj = new stdClass();  
    $obj->name = $name;  
    $obj->title = $title;  
    return $obj;  
}, $post1, $post2);  

// 打印结果  
print_r($result);  
?>