go 的 reflect 能按代码顺序获取 Method 吗？

package main

import (
    "fmt"
    "reflect"
    "runtime"
    "sort"
)

type MyService struct{}

func (s *MyService) F1() {}
func (s *MyService) F3() {}
func (s *MyService) F5() {}
func (s *MyService) F2() {}
func (s *MyService) F4() {}
func (s *MyService) F6() {}

func main() {
    s := &MyService{}
    rt := reflect.TypeOf(s)

    // 创建一个 map 用于存储行号和方法名
    methods := make(map[int]string)

    // 遍历方法名称和所在行号
    for i := 0; i < rt.NumMethod(); i++ {
        method := rt.Method(i)
        methodName := method.Name
        fn := runtime.FuncForPC(method.Func.Pointer())
        if fn != nil {
            _, line := fn.FileLine(0)
            methods[line] = methodName
        } else {
            fmt.Printf("Unable to get function information for method: %s\n", methodName)
        }
    }

    // 获取方法名称的切片
    var lines []int
    for line := range methods {
        lines = append(lines, line)
    }

    // 对行号进行排序
    sort.Ints(lines)

    // 按照升序输出
    for _, line := range lines {
        fmt.Printf("Line: %d, Method: %s\n", line, methods[line])
    }
}

输出：

Line: 12, Method: F1
Line: 13, Method: F3
Line: 14, Method: F5
Line: 15, Method: F2
Line: 16, Method: F4
Line: 17, Method: F6