做个记录周次计算,跨月根据天数占有的多少来判断应归为那个月的周次
实现功能如图:
A16D5FDF-AB5C-400F-BDE4-01C4AD04D427.png
代码如下:
public static function queryForAFewWeeks($lastMonday)
{
// 本月第一周的天数
$firstWeekDay = 0;
// 本月总天数
$monthDays = date('t', $lastMonday);
for ($i = 1; $i <= 7; $i++) {
$day = strtotime(date('Y-m-0' . $i, $lastMonday));
$isMonday = date("w", $day);
if ($isMonday == self::MONDAY) {
$firstWeekDay = date('d', strtotime(date('Y-m-0' . $i, $lastMonday)));
}
}
$weekly = (date('d', $lastMonday) - $firstWeekDay) / 7; // 4
$weeklyDays = $monthDays - date('d', $lastMonday); // 2
if ($weeklyDays > 3) {
$weekly++;
if ($firstWeekDay > 4) {
$weekly++;
}
} else {
return date('m', $lastMonday) + 1 . '月W1';
}
return date('m', $lastMonday) . '月W' . $weekly;
}
代码其实可以优化一下。