《L05 电商实战》
从零开发一个电商项目,功能包括电商后台、商品 & SKU 管理、购物车、订单管理、支付宝支付、微信支付、订单退款流程、优惠券等
《L03 构架 API 服务器》
你将学到如 RESTFul 设计风格、PostMan 的使用、OAuth 流程,JWT 概念及使用 和 API 开发相关的进阶知识。
zhuzixian520
最佳答案

楼上的解答很赞,你的这个需要应该是需要用到条件查询 case when then else end…

SELECT
    pid,
    uid,
    SUM( score ) AS score,
    MAX( created_at ) AS created_at,
    SUM( CASE WHEN type = 1 THEN score ELSE 0 END ) AS type1,
    SUM( CASE WHEN type = 2 THEN score ELSE 0 END ) AS type2,
    SUM( CASE WHEN type = 3 THEN score ELSE 0 END ) AS type3,
    SUM( CASE WHEN type = 4 THEN score ELSE 0 END ) AS type4
FROM
    demo_x
GROUP BY
    uid

亲测有效

Laravel

2年前 评论
讨论数量: 3
zhuzixian520

楼上的解答很赞,你的这个需要应该是需要用到条件查询 case when then else end…

SELECT
    pid,
    uid,
    SUM( score ) AS score,
    MAX( created_at ) AS created_at,
    SUM( CASE WHEN type = 1 THEN score ELSE 0 END ) AS type1,
    SUM( CASE WHEN type = 2 THEN score ELSE 0 END ) AS type2,
    SUM( CASE WHEN type = 3 THEN score ELSE 0 END ) AS type3,
    SUM( CASE WHEN type = 4 THEN score ELSE 0 END ) AS type4
FROM
    demo_x
GROUP BY
    uid

亲测有效

Laravel

2年前 评论

用sql麻烦的吧。 用php逻辑组合要方便得多吧

2年前 评论
SELECT
    MAX( uid ) uid,
    MAX( pid ) pid,
    SUM( score ) score,
    SUM( CASE WHEN type = 1 THEN score ELSE 0 END ) type1,
    SUM( CASE WHEN type = 2 THEN score ELSE 0 END ) type2,
    SUM( CASE WHEN type = 3 THEN score ELSE 0 END ) type3,
    MAX( created_at ) created_at 
FROM
    table 
GROUP BY
    uid

看一下是否符合你的要求。

2年前 评论
zhuzixian520

楼上的解答很赞,你的这个需要应该是需要用到条件查询 case when then else end…

SELECT
    pid,
    uid,
    SUM( score ) AS score,
    MAX( created_at ) AS created_at,
    SUM( CASE WHEN type = 1 THEN score ELSE 0 END ) AS type1,
    SUM( CASE WHEN type = 2 THEN score ELSE 0 END ) AS type2,
    SUM( CASE WHEN type = 3 THEN score ELSE 0 END ) AS type3,
    SUM( CASE WHEN type = 4 THEN score ELSE 0 END ) AS type4
FROM
    demo_x
GROUP BY
    uid

亲测有效

Laravel

2年前 评论

讨论应以学习和精进为目的。请勿发布不友善或者负能量的内容,与人为善,比聪明更重要!