[小白提问]string.Template里面可以赋为二级字典的值吗

也许你需要这样子做

结果是： NameError: name 'Template' is not defined

这个是需要导入的类库吗？

It cannot be done by using string.Template.

I build one for it, not test and not sure if anything failed.

import re


class Dict(dict):

    def __init__(self, d={}):
        super().__init__()
        for key, value in d.items():
            self[key] = Dict(value) if type(value) is dict else value

    def __getattr__(self, key):
        if key in self:
            return self[key]
        raise AttributeError(key) #Set proper exception, not KeyError

    __setattr__ = dict.__setitem__
    __delattr__ = dict.__delitem__


class Template():

    def __init__(self, template):
        self.template = template

    def repl(self, match):
        text = match.group(1)
        return str(eval("self.values."+text)) if text else "$"

    def format(self, values):
        self.values = Dict(values)
        return re.sub(r"\$(.*?)\$", self.repl, self.template, re.MULTILINE)


template = Template("""
Variable        : $var$
Escape          : $$
Variable in text: $test2.name$
""".strip())

values = {'var': 'foo','test':'11','test2':{'name':'qqq','class':'aaa'}}
print(template.format(values))

Variable        : foo
Escape          : $
Variable in text: qqq