在laravel中使用mysql 的if方法,提示语法错误的问题

laravel中查询数据使用mysql的if函数,提示语法错误,请问是什么问题?

$model = ApprovalRecord::query();
            $check_type = $request->get('check_type');
            if ($check_type == '已通过') {
                $model = $model->where('warrant_id',Auth::id());
                $model = $model->where('warrant_check',1);
            } else if ($check_type == '未通过') {
                $model = $model->where('warrant_id',Auth::id());
                $model = $model->where('warrant_check',2);
            } else {
                $model = $model->whereRaw('`warrant_id` IS NULL and if (`data_type` = 1,`control_id1` IS NOT NULL,`control_id1` IS NULL');
            }
            $res = $model->orderBy('id','desc')->paginate($request->get('limit',30))->toArray();

在navacat中确是可以执行成功的,